A) \[1.6\times {{10}^{-8}}\Omega \,m\]
B) \[1.6\times {{10}^{-7}}\Omega \,m\]
C) \[1.6\times {{10}^{-6}}\Omega \,m\]
D) \[1.6\times {{10}^{-5}}\Omega \,m\]
Correct Answer: D
Solution :
[d] \[V=IR=I\rho\frac{l}{A}\] \[\Rightarrow \rho =\frac{VA}{Il}=\frac{VA}{In\,e\,A{{v}_{d}}}=\frac{V}{l\times n\times e\times {{v}_{d}}}\] \[\Rightarrow \rho =\frac{5}{0.1\times 2.5\times {{10}^{-19}}\times 1.6\times {{10}^{-19}}\times 8\times {{10}^{28}}}\]\[=1.6\times {{10}^{-5}}\Omega \,m\]
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