A) 56
B) 63
C) 7
D) 49
Correct Answer: A
Solution :
[a] \[x=\sqrt[3]{7}+\sqrt[3]{49}\] \[\Rightarrow {{x}^{3}}=7+49+3\sqrt[3]{7}\sqrt[3]{49}(\sqrt[3]{7}+\sqrt[3]{49})=56+21x\] Or \[{{x}^{3}}-21x-56=0\] Therefore, the product of roots is 56.You need to login to perform this action.
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