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JEE Main & Advanced Chemistry Classification of Elements and Periodicity in Properties / तत्त्वों का वर्गीकरण एवं गुणों में आवर्ति Question Bank Mock Test - Classification Elements Periodicity Properties

  • question_answer
    Calculate the electronegativity of fluorine from the following data:
    \[{{E}_{H-H}}=104.2\,kcal\,mo{{l}^{-1}}\]
    \[{{E}_{F-F}}=36.6\,kcal\,mo{{l}^{-1}}\]
    \[{{E}_{H-F}}=134.6\,kcal\,mo{{l}^{-1}}\]
    \[{{X}_{H}}=2.1\]
    Express your answer to the nearest possible integral.

    Answer:

    4


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