question_answer

An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are \[{{t}_{1/8}}\] and \[{{t}_{1/10}}\] respectively. What is the value of\[\left[ \frac{{{t}_{1/8}}}{{{t}_{1/10}}} \right]\times 10\]? \[(lo{{g}_{10}}2=0.3)\,k=\frac{2.303}{t}\log \frac{[{{A}_{0}}]}{[A]}\]

Answer:

9