A) 0.10/K
B) 0.29/K
C) 0.69/K
D) 0.15/K
Correct Answer: B
Solution :
[b] \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] or \[k=\frac{2.303}{{{t}_{1/4}}}\log \frac{4a}{3a}=\frac{2.303}{{{t}_{1/4}}}\log \frac{4}{3}\] or \[k=\frac{2.303\times 0.125}{{{t}_{1/4}}}=\frac{0.29}{{{t}_{1/4}}}\]
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