question_answer

\[{{H}_{2}}O\] is dipolar, whereas \[Be{{F}_{2}}\] is not. It I because

A)  The electronegativity of F is greater than that of 0

B)  \[{{H}_{2}}O\] involves hydrogen bonding whereas \[Be{{F}_{2}}\] is a discrete molecule

C)  \[{{H}_{2}}O\] is linear and \[Be{{F}_{2}}\] is angular

D)  \[{{H}_{2}}O\] is angular and \[Be{{F}_{2}}\] is linear

Correct Answer: D

Solution :

[d] In a linear symmetrical molecule like \[\left[ Be{{F}_{2}} \right]\]the bond angle between three atoms is \[180{}^\circ \]hence the polarity due to one bond is cancelled by the equal polarity due to other bond, while it is not so in the case of angular molecules like \[{{H}_{2}}O\].