question_answer

Specify the coordination geometry around and hybridization Of N and B atoms in a 1 : 1 complex of \[B{{F}_{3}}\] and \[N{{H}_{3}}\]:

A)  N: tetrahedral, \[s{{p}^{3}}\], B: tetrahedral, \[s{{p}^{3}}\]

B)  N: pyramidal, \[s{{p}^{3}}\]', B: pyramidal, \[s{{p}^{3}}\]

C)  N: pyramidal, \[s{{p}^{3}}\], B: planar, \[s{{p}^{2}}\]

D)  N: pyramidal, \[s{{p}^{3}}\], B: tetrahedral, \[s{{p}^{3}}\]

Correct Answer: A

Solution :

[a] The 1: 1 complex both \[B{{F}_{3}}\]and \[N{{H}_{3}}\]is represented as follows: in this complex both N and B attain tetrahedral geometry and \[s{{p}^{3}}\]hybridization in the coordinately formed structure. During coordinate bond formation hybridized state of donor doesn?t change but hybridized state of acceptor changes.