A) \[{{C}^{2-}}_{2},{{O}^{-}}_{2}CO,NO\]
B) \[N{{O}^{+}}\],\[{{C}^{2-}}_{2},\]\[C{{N}^{-}},\]\[{{N}_{2}}\]
C) \[C{{N}^{-}},\]\[{{N}_{2}}\],\[{{O}^{2-}}_{2},\]\[{{C}^{2-}}_{2},\]
D) \[N{{O}_{2}}\],\[{{O}_{2}}\],\[N{{O}^{+}}\],\[CO\]
Correct Answer: B
Solution :
[c] \[N{{O}^{+}},{{C}^{2-}}_{2},C{{N}^{-}}\], and \[{{N}_{2}}\]all have 14 electrons.
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