A) \[H{{e}^{+}}_{2}\]
B) \[{{H}_{2}}\]
C) \[{{H}^{+}}_{2}\]
D) \[{{H}^{-}}_{2}\]
Correct Answer: B
Solution :
[b] \[H{{e}_{2}}^{+}\] and \[{{H}_{2}}^{-}\] have three electons, one must be unpaired. \[{{H}_{2}}^{+}\]has one unpaired electrons, whereas \[{{H}_{2}}\] has two electrons and thus diamagnetic.
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