A) \[p(1+e)\]
B) \[\frac{p}{1-e}\]
C) \[p\left( 1+\frac{1}{e} \right)\]
D) \[p\left( \frac{1+e}{1-e} \right)\]
Correct Answer: D
Solution :
[d] \[\Delta p=(p+ep)+(ep+{{e}^{2}}p)+({{e}^{2}}p+e{{p}^{3}})+...\] \[=p(1+e)[1+e+{{e}^{2}}+...]=\frac{p(1+e)}{(1-e)}\]You need to login to perform this action.
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