A) \[R'=eR\]
B) \[R'={{e}^{2}}R\]
C) \[R'=\frac{R}{e}\]
D) \[R'=R\]
Correct Answer: A
Solution :
[a]\[R=\frac{2u\cos \theta .u\sin \theta }{g}\] After impact horizontal component remains the same = u \[\cos \theta \] The vertical component becomes \[V=e(\sin \theta )\] New range \[{R}'=\frac{2u\cos \theta .eu\sin \theta }{g}{R}'=eR\]
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