question_answer

Identity X, Y and Z from the information given below: X = A chiral amino acid which loses its chirality on treatment with lithium aluminum hydride. Y= the decarboxylation product of a-amino (secondary) acid, \[{{C}_{5}}{{H}_{9}}{{O}_{2}}N\]. Z = It is formed when A (\[{{C}_{3}}{{H}_{4}}{{O}_{3}}\]) is treated with (i) \[N{{H}_{3}}\](ii) \[NaB{{H}_{4}}\] [A forms oxime, gives iodoform test and liberate \[C{{O}_{2}}\] with \[NaHC{{O}_{3}}\]].

A)

X	YZ
Alanine	Serine

B)

X	YZ
Serine	Alanine

C)

X	YZ
Serine	Alanine

D)

X	YZ
Aspartic acid	Serine

Correct Answer: C

Solution :

[c]