A) \[1.2\times {{10}^{14}}Hz\]
B) \[8\times {{10}^{15}}Hz\]
C) \[1.2\times {{10}^{16}}Hz\]
D) \[4\times {{10}^{12}}Hz\]
Correct Answer: B
Solution :
[b] \[KE=h{{v}_{0}}-h{{v}_{0}}\] \[h{{v}_{1}}-h{{v}_{0}}=2(h{{v}_{2}}-h{{v}_{0}})\] \[{{v}_{0}}=2({{v}_{2}}-{{v}_{1}})\] \[=2(2.0\times {{10}^{16}})-(3.2\times {{10}^{16}})\] \[=8\times {{10}^{15}}{{s}^{-1}}=8\times {{10}^{15}}HZ\]
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