2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Definite Integration

JEE Main & Advanced Mathematics Definite Integration Question Bank Mock Test - Application of Integrals

  • question_answer
    The area enclosed between the curves \[y=a{{x}^{2}}\] and \[x=a{{y}^{2}}\] (where a > 0) is 1 sq. unit, then the value of a is

    A) \[1/\sqrt{3}\]     

    B) ½

    C) 1                     

    D) 1/3

    Correct Answer: A

    Solution :

    [a] The area bounded by \[{{y}^{3}}=4ax\] and \[{{x}^{2}}=4by\] is \[\frac{16ab}{3}.\] Then the area bounded by \[{{y}^{2}}=x/a\] and \[{{x}^{2}}=y/a\] is \[\frac{1}{3{{a}^{2}}}.\] Given \[\frac{1}{3{{a}^{2}}}=1\Rightarrow a=\pm \frac{1}{\sqrt{3}}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner