A) -1
B) 1
C) 0
D) none of these
Correct Answer: A
Solution :
[a] Here, y>0. Putting \[y=x\] in \[y=\sqrt{4-x}\], we get\[x=\sqrt{2},-\sqrt{2.}\] So, the point is\[(\sqrt{2},\sqrt{2})\]. Differentiating \[{{y}^{2}}+{{x}^{2}}=4\]w.r.t. x, we get \[2y\frac{dy}{dx}+2x=0\] Or \[\frac{dy}{dx}=-\frac{x}{y}\] \[\therefore At(\sqrt{2},\sqrt{2}),\frac{dy}{dx}=-1\]You need to login to perform this action.
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