| 72 | 24 | 7 |
| 96 | 16 | 12 |
| 108 | ? | 18 |
A) 12
B) 16
C) 18
D) 20
Correct Answer: A
Solution :
In the first row, \[72\div \left( \frac{24}{2} \right)=6\]. In the second row, \[96\div \left( \frac{16}{2} \right)=12\] Let the missing number in the third row be x. Then, \[108\div \left( \frac{x}{2} \right)=18\]\[\Rightarrow \]\[\frac{x}{2}=\frac{108}{18}=6\] \[\Rightarrow \] \[x=12\]
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