JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    A compound microscope has an eye piece of focal length 10 cm and an objective of focal length 4 cm. Calculate the magnification, if an object is kept at a distance of 5 cm from the objective so that final image is formed at the least distance vision (20 cm)                                                              [UP SEAT 2005]

    A)            12  

    B)            11  

    C)            10  

    D)            13

    Correct Answer: A

    Solution :

                       For objective lens \[\frac{1}{{{f}_{o}}}=\frac{1}{{{v}_{o}}}-\frac{1}{{{u}_{o}}}\]                    Þ \[\frac{1}{{{v}_{o}}}=\frac{1}{{{f}_{o}}}+\frac{1}{{{u}_{o}}}\]\[=\frac{1}{4}+\frac{1}{-5}=\frac{1}{20}\]Þ \[{{v}_{o}}=20cm\]                    Now \[M=\frac{{{v}_{o}}}{{{u}_{o}}}\left( 1+\frac{D}{{{f}_{e}}} \right)\] \[=\frac{20}{5}\left( 1+\frac{20}{10} \right)\] \[=12\,.\]


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