A) \[51\text{ }c{{m}^{3}}\]
B) \[52\text{ }c{{m}^{3}}\]
C) \[53\text{ }c{{m}^{4}}\]
D) \[54\text{ }c{{m}^{2}}\]
E) None of these
Correct Answer: D
Solution :
Explanation Here, \[\operatorname{a} = 9 cm, b = 12 cm \,and \,c = 15 cm\] \[\therefore \,\,s=\frac{a+b+c}{2}\,\,=\,\,\frac{9+12+15}{2}=\frac{36}{2}=18\] \[Area\,\,=\,\,\sqrt{s(s-a)(s-b)(s-c)}\] \[=\,\,\,\sqrt{18(18-9)(18-12)(18-15)}\] \[=\,\,\,\sqrt{18\times 9\times 6\times 3}\,\,=\,\,54c{{m}^{2}}.\]
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