A) 2.91 m
B) 3 m
C) 5.82 m
D) None of these
E) None of these
Correct Answer: B
Solution :
Explanation \[\operatorname{Area} of park= (60\,\,\times \,\,40){{m}^{2}}-2400\,\,{{m}^{2}}\] \[\operatorname{Area} of the lawn\,\,=\,\, 2109{{m}^{2}}\] \[\therefore \] Area of the cross-roads \[= \left( 2400 - 2109 \right){{m}^{2}}= 291{{m}^{2}}\] Let the width of the road be x metres, then, \[60x+40x\,-{{x}^{2}}= 291\] \[\Rightarrow \,\,\,{{x}^{2}}-100x+291=0\] \[\Rightarrow \,\,\,\left( x-97 \right)\left( x-3 \right)=0\] \[\Rightarrow \,\,\,\,\operatorname{x}= 3.\]
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