question_answer

The area of an isosceles triangle with equal sides 5.1 meters and the third side 4.6 meters is

A) 10.47 sq. m       

B) 2.86 sq. m

C) 10.45 sq. m                 

D) None of these

Correct Answer: A

Solution :

    In right angled\[\Delta \,ADC,\] \[AD=\sqrt{{{(5.1)}^{2}}-{{2.3}^{2}}}=4.55\,m\] \[\therefore \]  Area of\[\Delta \,ABC=2.3\times 4.55=10.47\,\text{sq}\text{.}\,\text{m}\text{.}\]