question_answer

Two circles, each of unit radius, are so drawn that the centre of each lies on the circumference of the other. The area of the region, common to both the circles, is

A)  \[\frac{(4\pi -3\sqrt{3})}{12}\]                  

B)  \[\frac{(4\pi -6\sqrt{3})}{12}\]

C)  \[\frac{(4\pi -3\sqrt{3})}{6}\]      

D)         \[\frac{(4\pi -6\sqrt{3})}{6}\]