A) 2550
B) 2541
C) 2500
D) 2575
Correct Answer: B
Solution :
| [b] Number of bullets \[=\frac{{{(44)}^{3}}}{\frac{4}{3}\pi {{(2)}^{3}}}=\frac{{{(44)}^{3}}\times 3\times 7}{32\times 22}=2541\] |
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