JEE Main & Advanced Mathematics Statistics Question Bank Median and Mode

  • question_answer
    If a variable takes the discrete values \[\alpha -4,\,\alpha -\frac{7}{2},\,\alpha -\frac{5}{2},\,\alpha -3,\,\alpha -2,\,\alpha +\frac{1}{2},\,\alpha -\frac{1}{2},\,\alpha +5\,(\alpha >0)\], then the median is [DCE 1997; Pb. CET 1988]

    A)                 \[\alpha -\frac{5}{4}\]           

    B)                 \[\alpha -\frac{1}{2}\]

    C)                 \[\alpha -2\]          

    D)                  \[\alpha +\frac{5}{4}\]

    Correct Answer: A

    Solution :

                       Arrange the data as                    \[\alpha -\frac{7}{2},\alpha -3,\alpha -\frac{5}{2},\alpha -2,\alpha -\frac{1}{2},\alpha +\frac{1}{2},\alpha +4,\alpha +5\]                    Median\[=\frac{1}{2}[\text{value of }{{\text{4}}^{\text{th}}}\text{item}+\text{value of }{{\text{5}}^{\text{th}}}\text{item }\!\!]\!\!\text{ }\]                                 \ Median \[=\frac{\alpha -2+\alpha -\frac{1}{2}}{2}\] \[=\frac{2\alpha -\frac{5}{2}}{2}\]= \[\alpha -\frac{5}{4}\].


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