A) 6
B) 7
C) 8
D) None of these
Correct Answer: C
Solution :
Here, \[\bar{x}=\frac{2+4+6+8+10}{5}=6\] Hence, variance = \[\frac{1}{n}\Sigma {{({{x}_{i}}-\overline{x})}^{2}}\] \[=\frac{1}{5}\{{{(2-6)}^{2}}+{{(4-6)}^{2}}+{{(6-6)}^{2}}+{{(8-6)}^{2}}+{{(10-6)}^{2}}\}\] \[=\frac{1}{5}\left\{ (16+4+0+4+16 \right\}\]\[=\frac{1}{5}\left\{ 40 \right\}\] \[=8\].
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