A) \[{{x}_{1}}\]
B) \[{{x}_{51}}\]
C) \[\frac{{{x}_{1}}+{{x}_{2}}+...+{{x}_{101}}}{101}\]
D) \[{{x}_{50}}\]
Correct Answer: B
Solution :
Mean deviation is minimum when it is considered about the item, equidistant from the beginning and the end i.e., the median. In this case median is \[\frac{101+1}{2}th\] i.e., 51st item i.e., \[{{x}_{51}}\].
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