| x : | 2 | 3 | 4 | 5 | 6 |
| f : | 3 | 4 | 8 | 4 | 1 |
A) 0
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) 1
Correct Answer: D
Solution :
\[N=(\Sigma f)=20\] \[{{Q}_{1}}=\frac{(N+1)}{4}th\] observation \[={{\left( \frac{21}{4} \right)}^{th}}\]observation=3 Similarly, \[{{Q}_{3}}=3\left( \frac{N+1}{4} \right)\ th\] observation \[=\left( \frac{63}{4} \right)\ th\] observation = 5 Now Q.D. \[=\frac{1}{2}\left( {{Q}_{3}}-{{Q}_{1}} \right)=\frac{1}{2}\left( {{Q}_{3}}-{{Q}_{1}} \right)\]\[=\frac{1}{2}(5-3)=1\].
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