JEE Main & Advanced Mathematics Statistics Question Bank Measures of dispersion

  • question_answer
    For a frequency distribution, standard deviation is computed by

    A)                 \[\sigma =\frac{\sum f(x-\bar{x})}{\sum f}\]      

    B)                 \[\sigma =\frac{\sqrt{\sum f{{(x-\bar{x})}^{2}}}}{\sum f}\]

    C)                 \[\sigma =\sqrt{\frac{\sum f{{(x-\bar{x})}^{2}}}{\sum f}}\]

    D)                 \[\sigma =\sqrt{\frac{\sum f(x-\bar{x})}{\sum f}}\]

    Correct Answer: C

    Solution :

                    It is obvious.


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