JEE Main & Advanced Mathematics Statistics Question Bank Measures of dispersion

  • question_answer
    For a frequency distribution standard deviation is computed by applying the formula       [Kurukshetra CEE 1999]

    A)                 \[\sigma =\sqrt{\left( \frac{\sum \,fd}{\sum \,f} \right)-\frac{\sum \,f{{d}^{2}}}{\sum \,f}}\]        

    B)                 \[\sigma =\sqrt{\frac{\sum \,f{{d}^{2}}}{\sum \,f}-{{\left( \frac{\sum \,f{{d}^{2}}}{\sum \,f} \right)}^{2}}}\]

    C)                 \[\sigma =\sqrt{{{\left( \frac{\sum \,fd}{\sum \,f} \right)}^{2}}-\frac{\sum \,f{{d}^{2}}}{\sum \,f}}\]            

    D)                 \[\sigma =\sqrt{\frac{\sum \,f{{d}^{2}}}{\sum \,f}-{{\left( \frac{\sum \,fd}{\sum \,f} \right)}^{2}}}\]

    Correct Answer: D

    Solution :

                    It is obvious.


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