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5th Class Mathematics Measurement Length, Weight and Capacity Question Bank Measurements

  • question_answer
     The given table shows the prices of 3 different types of eggs. \[\frac{1}{4}\] of the eggs 4 Priyanka bought were chicken eggs. \[\frac{1}{8}\] of them were century eggs and the rest were quail eggs. If Priyanka spent a total amount of Rs. 6.50 on the chicken and century eggs, how much did she spend on the quail eggs?
    Chicken eggs 20 Paise each
    Century eggs 90 Paise each
    Quail eggs 5 Paise each

    A)   Rs. 1.25         

    B)  Rs. 1.40           

    C)  Rs. 1.65           

    D)  Rs. 1.80

    Correct Answer: A

    Solution :

    Let the total number of eggs be X. \[\therefore \]Number of chicken eggs \[=\frac{1}{4}X\] Number of century eggs \[=\frac{1}{8}X\] And number of quail eggs \[=X-\left( \frac{1}{4}X+\frac{1}{8}X \right)=\frac{5}{8}X\] Now, \[\frac{1}{4}\times X\times 20+\frac{1}{8}\times X\times 90=6.50\times 100\]paise \[\Rightarrow \] \[\frac{40X+90X}{8}=650\] \[\Rightarrow \]\[130X=\text{ }5200\]\[\Rightarrow \] \[X=40\] \[\therefore \]Number of quail eggs \[=\frac{5}{8}\times 40=25\] So, money spent on quail eggs \[=\text{ }\left( 25\times 5 \right)\]paise \[=\text{ }125\]paise = Rs. 1.25.


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