A) \[\text{8}\sqrt{2}\text{ cm}\]
B) \[2\sqrt{8}\text{ cm}\]
C) \[4\sqrt{2}\text{ cm}\]
D) \[2\sqrt{2}\text{ cm}\]
Correct Answer: A
Solution :
| [a] Let side of square = x cm |
| By Pythagoras theorem. |
| \[{{x}^{2}}+{{x}^{2}}={{(16)}^{2}}=256\] |
| \[2{{x}^{2}}=256\] |
| \[{{x}^{2}}=128\,\,\,\,\Rightarrow \,\,\,\,x=8\sqrt{2}\,cm\] |
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