A) a
B) \[\frac{a}{2}\]
C) \[\frac{\sqrt{3}a}{2}\]
D) \[\frac{2a}{\sqrt{3}}\]
Correct Answer: C
Solution :
[c] The interionic distance for CsCl is between \[C{{S}^{+}}\] and \[C{{S}^{-}}\] ion which is present at the body center and at a corner respectively, i.e. half of the length of diagonal \[=\frac{\sqrt{3}a}{2}.\]You need to login to perform this action.
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