A) The solution turns blue
B) The solution gets decolourised
C) \[S{{O}_{2}}\] is reduced
D) Green \[C{{r}_{2}}{{\text{(}S{{O}_{4}}\text{)}}_{3}}\] is formed
Correct Answer: A
Solution :
[a]| According to this reaction, green colour \[C{{r}_{2}}{{(S{{O}_{4}})}_{3}}\] is formed, when \[S{{O}_{2}}\] is passed through acidified \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] solution. |
| \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}+3S{{O}_{2}}\to {{K}_{2}}S{{O}_{4}}+\underset{(Green)}{\mathop{C{{r}_{2}}{{(S{{O}_{4}})}_{3}}}}\,+3{{H}_{2}}O\] |
You need to login to perform this action.
You will be redirected in
3 sec
