A) Terminating
B) Non-terminating repeating
C) Non-terminating non-repeating
D) None of the above
Correct Answer: B
Solution :
| Sol. [b] We have, \[\frac{368}{1050}=\frac{184}{525}=\frac{{{2}^{3}}\times 23}{{{5}^{2}}\times 3\times 7}\] |
| Clearly, prime factorisation of the denominator is not of the form \[{{2}^{m}}\times {{5}^{n}}.\] Hence, decimal expansion of \[\frac{368}{1050}\] is non-terminating repeating. |
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