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10th Class Mathematics Real Numbers Question Bank MCQs - Real Numbers

  • question_answer
    The least number which when divided by 18, 24, 30 and 42 will leave in each case the same remainder 1, would be:

    A) 2520

    B) 2519

    C) 2521

    D) None of these

    Correct Answer: C

    Solution :

    Sol. [c] We have, \[18=2\times {{3}^{2}},\,24={{2}^{3}}\times 3\]
    \[30=2\times 3\times 5,\,\,42=2\times 3\times 7\]
    \[LCM={{2}^{3}}\times {{3}^{2}}\times 5\times 7=2520\]
    So, required least number is \[2520+1=2521\]


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