A) \[\text{3}.\text{5}0\text{8}\]
B) \[\text{2}.\text{248}\]
C) \[\text{5}.\text{69}\]
D) \[0.\text{248}\]
Correct Answer: D
Solution :
| Sol. [d] Given, rational number is \[\frac{31}{125}\] |
| \[\therefore \] Prime factorisation of \[125={{5}^{3}}\] |
| Now, \[\frac{31}{125}=\frac{31}{{{5}^{3}}}=\frac{31\times {{2}^{3}}}{{{5}^{3}}\times {{2}^{3}}}=\frac{248}{{{10}^{3}}}=0.248\] |
| Thus, \[\frac{31}{125}\] has decimal expansion, which terminate. |
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