10th Class Mathematics Real Numbers Question Bank MCQs - Real Numbers

  • question_answer
    The greatest number which divides 121,226 and 259 and leaves remainders 1, 2 and 3 respectively is:

    A) 8

    B) 16

    C) 24

    D) None of these

    Correct Answer: A

    Solution :

    Sol.      [a] The required greatest number is HCF of \[(121-1),\]\[(226-2)\]and \[(259-3)\] i.e., 120. 224 and 256.
                            \[120=2\times 2\times 2\times 3\times 5={{2}^{3}}\times 3\times 5\]
                            \[224=2\times 2\times 2\times 2\times 2\times 7={{2}^{5}}\times 7\]
    and       \[256=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2={{2}^{8}}\]
    \[\therefore \,\,\,\,\,\,\,HCF(120,224,256)={{2}^{3}}=8\]


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