A) 20
B) 10
C) 50
D) 80
Correct Answer: B
Solution :
| Sol. [b] \[20=2\times 2\times 5={{2}^{2}}\times 5\] |
| \[50=2\times 5\times 5=2\times {{5}^{2}}\] |
| and \[80=2\times 2\times 2\times 2\times 5={{2}^{4}}\times 5\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,HCF\,\,(20,50,80)=2\times 5=10\] |
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