| There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girts alone. |
| The total number of sections thus formed are: |
A) 22
B) 16
C) 36
D) 21
Correct Answer: B
Solution :
| Sol. [b] HCF of 576 and \[\text{448}=\text{64}\] |
| \[\therefore \] Number of sections |
| \[=\frac{576}{64}+\frac{448}{64}=9+7=16\] |
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