A) \[\frac{2}{15}\]
B) \[\frac{11}{160}\]
C) \[\frac{17}{60}\]
D) \[\frac{6}{35}\]
Correct Answer: B
Solution :
| Sol. [b] \[\frac{11}{160}=\frac{11}{{{2}^{5}}\cdot 5}\] |
| Denominator is of the form \[{{2}^{m}}\cdot {{5}^{n}}\] |
| \[\therefore \] its decimal expansion is terminating. |
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