10th Class Mathematics Real Numbers Question Bank MCQs - Real Number

  • question_answer
    On the basis of form \[{{2}^{m}}\times {{5}^{n}}\]of denominator that \[\frac{1458}{1250}\]will be expanded in decimal upto places will be

    A) one

    B) two

    C) three

    D) four

    Correct Answer: D

    Solution :

    We have, \[\frac{1458}{1250}=\frac{1458}{2\times {{5}^{4}}}\]
     \[=\frac{1458\times {{2}^{3}}}{2\times {{5}^{4}}\times {{2}^{3}}}=\frac{11664}{{{\left( 2\times 5 \right)}^{4}}}\]
    =\[\frac{11664}{{{10}^{4}}}=\frac{11664}{10000}\]
     = 1.1664
    So, it will terminates after 4 places of decimals.
     


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