A) 0.104
B) 1.04
C) 0.0104
D) 0.140
Correct Answer: A
Solution :
Given rational number is \[\frac{13}{125}\] |
\[\therefore\] Prime factorisation of \[125={{5}^{3}}\] |
Now, \[\frac{13}{125}=\frac{13}{{{5}^{3}}}=\frac{13\times {{2}^{3}}}{{{5}^{3}}\times {{2}^{3}}}=\frac{104}{{{10}^{3}}}=0.104\] |
[make the denominator in the power of 10] |
Thus, \[\frac{13}{125}\] has decimal expansion, which terminates. |
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