A) 3,140
B) 12,420
C) 3,420
D) 420,3
Correct Answer: C
Solution :
| We have, \[12=2\times 2\times 3={{2}^{2}}\times 3\] |
| \[15=3\times 5\] |
| \[21=3\times 7\] |
| \[\because\] HCF = product of smallest power of each common prime factor in the number = 3 and LCM = product of greatest power of each prime factor involved in the number |
| \[={{2}^{2}}\times 3\times 5\times 7\text{ }=420\] |
| Thus, HCF and LCM are 3 and 420, respectively. |
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