A) 12
B) 9
C) 10
D) 14
Correct Answer: C
Solution :
Let x be number of fruits in one row such that each fruit contains same number of fruits. i.e. x = HCF of (24, 36, 60) |
The factors of 24, 36 and 36 are |
\[24\text{ }=2\times 2\times 2\times 3\] |
\[36\text{ }=2\times 2\times 3\times 3\] |
\[60=2\times 2\times 3\times 5\] |
\[x=2\times 2\times 3=12\] |
So, peaches have \[12\times 2=2\] rows, apricots have \[12\times 3=3\]rows and bananas have \[12\times 5=60,\] 5 rows. Minimum number of rows =2 + 3 + 5 = 10 |
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