A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
By prime factorisation method, factors of 65 and 117 are given as, |
\[65=5\times 13\] |
and \[117={{3}^{2}}\times 13\] |
\[\therefore \,\,\,HCF\left( 65,117 \right)=13\] ... (i) |
According to the question, we have |
65m-117= HCF (65, 117) |
\[\Rightarrow 65m-117=13\] |
\[65m=13+117\] |
\[65m=130\] |
\[\Rightarrow m=2\] |
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