A) \[\frac{5}{13}\]
B) \[\frac{5}{14}\]
C) \[\frac{6}{13}\]
D) \[\frac{7}{13}\]
Correct Answer: B
Solution :
There are 14 = (5 + 9) fish out of which one can be chosen in 14 ways. \[\therefore \]Total numbers of possible outcomes =14 There are 5 male fish out of which one male fish can be chosen in 5 ways. \[\therefore \]Favourable number of elementary events = 5 Hence, required probability \[=\frac{5}{14}\]
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