A) \[\frac{2}{5}\]
B) \[\frac{3}{5}\]
C) \[\frac{4}{5}\]
D) \[\frac{1}{5}\]
Correct Answer: A
Solution :
Out of 20 tickets numbered from 1 to 20, one can be chosen in 20 ways. So, total number of possible outcomes associated with the given random experiment is 20. Out of 20 tickets numbered 1 to 20, tickets bearing numbers which are multiple of 3 or 7 bear numbers 3, 6, 7, 9, 12, 14, 15 and 18. \[\therefore \]Favourable number of elementary events =8 Hence, required probability \[=\frac{8}{20}=\frac{2}{5}\]
You need to login to perform this action.
You will be redirected in
3 sec
