A) \[\frac{3}{7}\]
B) \[\frac{4}{9}\]
C) \[\frac{5}{9}\]
D) \[\frac{7}{9}\]
Correct Answer: C
Solution :
Number x can be selected in three ways and corresponding to each such way there are three ways of selecting number y. Therefore, two numbers can be selected in 9 ways as listed below (1,1), (1,4), (1,9), (2,1), (2,4), (2,9), (3,1), (3,4), (3,9) So, total numbers of possible outcomes = 9 The product xy will be less than 9, if x and y are chosen in one of the following ways (1, 1), (1,4), (2,1), (2,4), (3.1) \[\therefore \]Favourable number of elementary events = 5 Hence, required probability \[=\frac{5}{9}\]
You need to login to perform this action.
You will be redirected in
3 sec
