A) \[\frac{2}{5}\]
B) \[\frac{4}{5}\]
C) \[\frac{1}{5}\]
D) \[\frac{3}{5}\]
Correct Answer: D
Solution :
Clearly, number x can take any one of the five given values. So, total number of possible outcomes = 5. We observe that \[{{x}^{2}}<2\] when x takes any one of the following three values -1, 0 and 1. So, favourable number of elementary events = 3 Hence, \[P\left( {{x}^{2}}<2 \right)=\frac{3}{5}\]
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