A) \[\frac{1}{26}\]
B) \[\frac{1}{13}\]
C) \[\frac{2}{13}\]
D) \[\frac{7}{13}\]
Correct Answer: A
Solution :
| [a] In a well-shuffled pack of 52 cards. |
| Total no. of possible outcomes = 52 |
| In a pack of 52 cards, there are 26 red cards, in which only 2 red kings. |
| So. total No. of favourable outcomes (red king) =2 |
| \[\therefore \] P(a red king) |
| \[=\frac{\text{No}.\text{ of favourable outcomes}}{\text{No}.\text{ of possible outcomes}}=\frac{2}{52}=\frac{1}{26}\] |
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