A) \[\frac{5}{18}\]
B) \[\frac{2}{9}\]
C) \[\frac{8}{15}\]
D) \[\frac{5}{9}\]
Correct Answer: D
Solution :
Total number of outcomes \[=6\times 6\times 6=216\] Number of favourable outcomes \[=6\times 5\times 4=120\] \[\therefore \]Required probability \[=\frac{120}{216}=\frac{5}{9}\]
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